461. Hamming Distance
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integersx
andy
, calculate the Hamming distance.
Note:
0 ≤x
,y
< 2^31
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
X X
The above X point to positions where the corresponding bits are different.
Solution:
The idea is to get the bit from right to left and compare them to count the number of differences.
public int hammingDistance(int x, int y) {
int res = 0;
for (int i = 0; i <= 31; i++) {
if (((x>>i)&1) != ((y>>i)&1)) {
res++;
}
}
return res;
}